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[ adverb ] in an algebraic manner
Examples "algebraically determined" Used in print (Kenneth Hoffman and Ray Kunze, Linear Al...)First , T may not have a single characteristic value ; this is really a deficiency in the scalar_field , namely , that it is not algebraically closed . Let V be a finite dimensional vector space over an algebraically closed field F , e.g. , the field of complex_numbers . From these results , one sees that the study of linear_operators on vector spaces over an algebraically closed field is essentially reduced to the study of nilpotent operators . For vector spaces over non algebraically closed fields , we still need to find some substitute for characteristic values and vectors . |
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